#125

Valid Palindrome

easy· Two Pointersruns: 0

A phrase is a palindrome if, after converting all uppercase letters into lowercase letters and removing all non-alphanumeric characters, it reads the same forward and backward. Given a string s, return true if it is a palindrome, otherwise return false.

wpm 0acc 100%time 0:000 / 440

class Solution:
    def isPalindrome(self, s: str) -> bool:
        left, right = 0, len(s) - 1
        while left < right:
            while left < right and not s[left].isalnum():
                left += 1
            while left < right and not s[right].isalnum():
                right -= 1
            if s[left].lower() != s[right].lower():
                return False
            left += 1
            right -= 1
        return True

click the box to focus · tab inserts 4 spaces · backspace to correct · esc to pause

desktop only

codedrill is a typing game and needs a real keyboard. open this on a laptop or desktop to practice.

you can still browse problems and sections from your phone.